Enter Your PSEUDONYM:         

Question 1:    Which of the following is TRUE about the decimal number 276?

                          The Binary representation would require 7 bits
                          The rightmost bit in the binary representation would be '0'
                          The rightmost bit in the binary representation would be '1'
                          A and B
                          A and C

Question 2:    The number 37 (decimal) in binary would be:

                          110101
                          100111
                          100101
                          110101
                          110001

 Question 3:    Adding the binary digits 10011 and 11001 together yields the binary number:

                          111010
                          110011
                          101100
                          110101
                          101110

Question 4:    If I add the character '1' and the character '6' together, I will get:

                          The character '7'
                          The number 7
                          The character 'e'
                          The character 'g'
                          You can’t add characters together

Question 5:    The number 74 (decimal) in Hex would be:

                          47
                          4A
                          74
                          7A
                          A4

Question 6:    The number 67 (Octal) in Binary would be:

                          001111
                          010111
                          110011
                          110111
                          111011

Question 7:    The Easiest way to convert between Octal and Hex is:

                          Convert to binary and then to Hex
                          Convert to decimal and then to Hex
                          Convert directly to Hex by multiplying by 2 (since 8 * 2 is 16)
                          Convert directly to Hex by adding 8 (since 8 + 8 is 16)
                          None of the above

Question 8:    All of the following are true about the data type char (in C/C++), EXCEPT:

                          it is unsigned
                          it is stored on 8-bits
                          it corresponds to the ASCII scheme
                          takes on values from -2^7 to +2^7 - 1
                          takes on values from -128 to +127

Question 9:    If I make the C/C++ declaration: char a = 109; I am:

                          defining a as a character variable and initializing it with the numeric value 109
                          asking for 8-bits of storage at location a in RAM and initializing it
                          storing the character ‘m’ at location a in RAM
                          A and B
                          All of the above

Question 10:  If I make the C/C++ declaration: char a = '3'; Location a will contain the bit sequence:

                          00000011
                          00110011
                          00111011
                          00111011
                          00111011