Enter Your PSEUDONYM:           

Question 1:    The number 73 requires ___ bits in binary:

                            6
                          7
                          8
                          9
                          10

Question 2:    The number 101110 (binary) in decimal would be:

                            42
                          43
                          44
                          45
                          46

Question 3:    Adding the binary digits 10011 and 11001 together yields the binary number:

                            111010
                          110011
                          101100
                          110101
                          101110

Question 4:    The Character 'M' is really:

                            The number 79 (base 10)
                          The number 1,000 (base 10)
                          The number 115 (base 8)
                          The number 79 (base 16)
                          The number 1001111 (base 2)

Question 5:    The number 53 (Octal) in Decimal would be::

                            35
                          43
                          45
                          53
                          55

Question 6:    The number 3B (Hex) in Binary would be:

                            001111
                          010111
                          110011
                          110111
                          111011

Question 7:    The Easiest way to convert between Octal and Hex is:

                            Convert to binary and then to Hex
                          Convert to decimal and then to Hex
                          Convert directly to Hex by multiplying by 2 (since 8 * 2 is 16)
                          Convert directly to Hex by adding 8 (since 8 + 8 is 16)
                          None of the above

Question 8:    If I make the C/C++ declaration: char a; I am:

                            defining a as a character
                          asking for 8-bits of storage at location a in RAM
                          initializing a with the numeric value 97
                          A and C
                          B and C

Question 9:    If I make the C/C++ declaration: char a = 109; I am:

                            defining a as a character variable and initializing it with the numeric value 109
                          asking for 8-bits of storage at location a in RAM and initializing it
                          storing the character ‘m’ at location a in RAM
                          A and B
                          All of the above

Question 10:  If I make the C/C++ declaration: char a = '3'; Location a will contain the bit sequence:

                            00000011
                          00110011
                          00111011
                          00111011
                          00111011