5.0030. Given:

struct datatemplate

{ char group[3];

int groupclass;

struct datatemplate *next; };

char main()

{ struct datatemplate data[3] = { {“AB”,76,6741},{“X4”,322,6732},

{“6T”,0,6750}};

If we issue the statement: printf(“%lu”, data)

And we receive the output: 6732

C. What would be printed by the statement: printf(“%lu”, &data[1]);

We know that the base address of data is 6732. We further know that each element (record) in the array requires 9 bytes of storage, so the address of data[1] is 6732 + 9 = 6741