5.0010. Given the following sections of C code:

struct emp

{ char lname[7], dept[5];

short age, class;

float salary;

};

void main()

{ struct emp employee[6];

printf (“%lu\n”, &employee[2].class); // The output would be 6420

b. What would be printed out by the command: printf(“%lu”, &employee[4].dept);

From Part a we know that employee == 6366

Therefore: &employee[4] == 4 * 20 + 6366 = 80 + 6366 = 6446

Therefore: &employee[4].dept = 6446 + 7 = 6453