5.0010. Given the following sections of C code:

struct emp

{ char lname[7], dept[5];

short age, class;

float salary;

};

void main()

{ struct emp employee[6];

printf (“%lu\n”, &employee[2].class); // The output would be 6420

a. What would be printed out by the command: printf(“%lu”, employee);

Since the address of &employee[2].age is 6420

then &employee[2] is: 6420 – 2 – 5 – 7 = 6406

If the address of &employee[2] is 6406 and each record requires:

7 + 5 + 2 + 2 + 4 = 20 bytes

Then the address of employee (== &employee[0]) = 6408 - 2 * 20 = 6406 – 40 = 6366