10.02.c. Show exactly how and where mystring would be stored?

We know that the base address of mystring is 4078 (Given).

We also know the string has been initialized as “Hi” (Given).

We also know (from previous sections) that:

‘H’ = ASCII 71 (‘A’ is ASCII 65) = 01000001₂

‘i’ = ASCII 105 (‘a’ is ASCII 97) = 01100001₂

We also know that the string must be terminated by the Null Character (’\0’) = 0₁₀ = 00000000₂

Therefore, looking at RAM we see:

4078	4079	4080	4081
01000001	01100001	00000000