10.02.a. What would the command: printf(“%d”, myshort[0]); yield?

Since &myshort[3] == 4066 (given) then &myshort[0] == 4066 – 3 * 2 == 4060

When we go to address 4060, we find the bit pattern:

0000000000101111 (On 16-bits)

Evaluating:

2⁵ + 2³ + 2² + 2¹ + 2⁰ = 32 + 8 + 4 + 2 + 1 = 47