100.0024 Given: long double longdoublenumber[50];

If the base address of longdoublenumber is 43768, what would the following command produce?

Printf(“%lu”, & longdoublenumber [187]);

43768 + 187 * 16 = 43768 + 2992 = 46760

NOTE: Once again, even though the subscript (offset) is outside the range requested, the calculated address is still valid