Record Size:

struct studentinfo { struct studentinfo *previousgpa; 4 bytes

char ssn[11], name[28], address[30]; 11 + 28 + 30 = 69 Bytes

short age, IQ; 2 + 2 = 4 Bytes

float gpa, balance; 4 + 4 = 8 Bytes

struct studentinfo *nextbalance; }; 4 Bytes

---

89 Bytes

Given: printf (“%lu\n”, &student[2].name); yields the output: 8625

Then: &student[2] => 8625 - 11 – 4 = 8610

And: student = 8610 – 2 * 89 = 8610 – 178 = 8432

The Linked Table below shows all of the addresses and links:

Highgpa Lowbalance

8432

8788

Addr	Sub	Previgpa	ssn	name	address	age	IQ	gpa	balance	nextbal
8432	0	8521	1234…	Gates	99 Microsoft	47	108	3.87	4500	NULL
8521	1	8699	2345…	Ford	17 Michigan	125	115	3.10	250	8699
8610	2	NULL	3456…	Trump	1 Trump	65	86	1.86	1500	8432
8699	3	8788	4567…	Astor	20 Wall	116	100	2.76	800	8610
8788	4	8610	5678…	Carnegie	100 Steel	81	79	2.25	0	8521

For each of the following printf statements, show the output which would be obtained:

a. printf(“%lu\n”,highgpa); 8432

b. printf(“%lu\n”,&highgpa); Unknown (this is NOT a trick question)

c. printf(“%lu\n”,lowbalance); 8788

d. printf(“%s\n”, student[4].previousgpa->previousgpa); 8610 -> NULL

e. printf(“%lu\n”,&student[2]. IQ);

&student[2] == 8610, so &student[2].IQ == 8610 + 4 +11 + 28 + 30 = 8683

f. printf(“%s\n”,student[3].nextbalance->nextbalance->name);

8610 -> 8432 -> Gates

g. printf(“%lu\n”, ++lowbalance); 8788 + 89 = 8877

h. if I first enter the command: arecord = record[4].nextbalance; what will be printed out by the command:

printf(“%d\n\n”, ++arecord->age); arecord = 8521

++arecord = 8521 + 89 = 8610

8610 -> age = 65

a. printf(“%lu\n”,&student[10].address); BA + offset * #bytes/record + field offset

= 8432 + 10 * 89 + 4 + 11 + 28

= 9372