100.0110.C. What would be printed out by the statement:
cout << ((b == 2) && (d > 4)
|| (e == 4) || (c > b));
Why??
((b
== 2) && (d > 4) || (e == 4) || (c > b))
= ((2 == 2) && (4 > 4) ||
(5 == 4) || (3 > 2))
= ((TRUE) && (FALSE) ||
(FALSE) || (TRUE))
= (FALSE || FALSE || TRUE)
= TRUE (= 1)